The physics
A projectile — a thrown ball, a water jet, a long jumper — follows a parabola because gravity only pulls vertically while horizontal motion continues unchanged.
How far a water jet at 10 m/s and 60° reaches
Answer: range = 8.83 m (max height 3.82 m, flight time 1.77 s).
What we know
- Launch speed: 10 m/s
- Launch angle: 60°
Nozzle at ground level; air drag ignored.
Step by step
- Given
- v₀ = 10 m/s, θ = 60°
- Formula
- R = v₀² · sin(2θ) / g
- Substitute
- R = 10² × sin(2 × 60) / 9.80665
- Result
- R = 8.83 m
All results
| Range | 8.83 m |
|---|---|
| Max height | 3.82 m |
| Flight time | 1.77 s |
Open the projectile motion calculator with these numbers → and change any of them.