Range of a javelin thrown at 28 m/s and 35°

Answer: range = 75.12 m (max height 13.15 m, flight time 3.28 s).

What we know

  • Launch speed: 28 m/s
  • Launch angle: 35°

Release height and aerodynamics ignored.

Step by step

Given
v₀ = 28 m/s, θ = 35°
Formula
R = v₀² · sin(2θ) / g
Substitute
R = 28² × sin(2 × 35) / 9.80665
Result
R = 75.12 m

All results

Range75.12 m
Max height13.15 m
Flight time3.28 s

Open the projectile motion calculator with these numbers → and change any of them.

The physics

A projectile — a thrown ball, a water jet, a long jumper — follows a parabola because gravity only pulls vertically while horizontal motion continues unchanged.