Range of a ball thrown at 20 m/s and 30°

Answer: range = 35.32 m (max height 5.1 m, flight time 2.04 s).

What we know

  • Launch speed: 20 m/s
  • Launch angle: 30°

No air resistance, launched and landing at the same height.

Step by step

Given
v₀ = 20 m/s, θ = 30°
Formula
R = v₀² · sin(2θ) / g
Substitute
R = 20² × sin(2 × 30) / 9.80665
Result
R = 35.32 m

All results

Range35.32 m
Max height5.1 m
Flight time2.04 s

Open the projectile motion calculator with these numbers → and change any of them.

The physics

A projectile — a thrown ball, a water jet, a long jumper — follows a parabola because gravity only pulls vertically while horizontal motion continues unchanged.