Heat to warm 150 kg of bath water by 25 °C

Answer: heat energy = 15,697,500 J (heat energy 15,697.5 kJ, heat energy 4,360.417 Wh).

What we know

  • Mass: 150 kg
  • Specific heat capacity: 4186 J/(kg·K)
  • Temperature change: 25 K (or °C)

Step by step

Given
m = 150 kg, c = 4186 J/(kg·K), ΔT = 25 K (or °C)
Formula
Q = m × c × ΔT
Substitute
Q = 150 × 4186 × 25
Result
Q = 15,697,500 J

All results

Heat energy15,697,500 J
Heat energy15,697.5 kJ
Heat energy4,360.417 Wh

Open the specific heat calculator with these numbers → and change any of them.

The physics

Specific heat capacity is how stubborn a substance is about changing temperature: the energy needed to warm one kilogram by one degree. Multiply it by the mass and by the temperature change and you get the total heat energy, Q — the number that quietly governs your kettle, your radiator and your heating bill.