Slackline tension: 70 kg with the line at 10°

Answer: tension in each rope = 1,976.599 N (horizontal pull at each anchor 1,946.57 N).

What we know

  • Hanging mass: 70 kg
  • Rope angle above horizontal: 10°

Step by step

Given
m = 70 kg, θ = 10°
Formula
T = m·g / (2·sin θ)
Substitute
T = 70 × 9.80665 / (2 × sin 10)
Result
T = 1,976.599 N

All results

Tension in each rope1,976.599 N
Horizontal pull at each anchor1,946.57 N

Open the two-rope tension calculator with these numbers → and change any of them.

The physics

A weight hung from two symmetric ropes — a sign between two posts, a lamp on a cable, a load on a sling — is a static equilibrium problem. The two rope tensions must together support the full weight vertically while their horizontal components cancel, because the mass is not going anywhere.

Standard acceleration of gravity →